Line slope calculator x+5y=16


Enter coordinates of two different points:

Straight line given by points A[1; 3] and B[6; 2]

Calculation:

Slope-intercept form of line: y = -0.2x+3.2

Canonical form of the line equation: x+5y-16 = 0

Parametric form of the line equation:
x = 5t+1
y = -t+3      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 16

Y intercept: y0 = q = 3.2

Distance line from the origin: d0 = 3.1379

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [3.5; 2.5]

Perpendicular Bisector equation: 5x-y-15 = 0


Vector OA = (1; 3) ;   |OA| = 3.1623
Vector OB = (6; 2) ;   |OB| = 6.3246
Scalar product OA .OB = 12
Angle ∠ AOB = 53°7'48″ = 0.9273 rad