Line slope calculator x-5y=-14
Straight line given by points A[1; 3] and B[6; 4]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+2.8
Canonical form of the line equation: x-5y+14 = 0
Parametric form of the line equation:
x = 5t+1
y = t+3 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -14
Y intercept: y0 = q = 2.8
Distance line from the origin: d0 = 2.7456
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [3.5; 3.5]
Perpendicular Bisector equation: 5x+y-21 = 0
Vector OA = (1; 3) ; |OA| = 3.1623
Vector OB = (6; 4) ; |OB| = 7.2111
Scalar product OA .OB = 18
Angle ∠ AOB = 37°52'30″ = 0.661 rad