Line slope calculator 3x-5y=-12
Straight line given by points A[1; 3] and B[6; 6]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x+2.4
Canonical form of the line equation: 3x-5y+12 = 0
Parametric form of the line equation:
x = 5t+1
y = 3t+3 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = -4
Y intercept: y0 = q = 2.4
Distance line from the origin: d0 = 2.058
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [3.5; 4.5]
Perpendicular Bisector equation: 5x+3y-31 = 0
Vector OA = (1; 3) ; |OA| = 3.1623
Vector OB = (6; 6) ; |OB| = 8.4853
Scalar product OA .OB = 24
Angle ∠ AOB = 26°33'54″ = 0.4636 rad