Line slope calculator x+6y=19


Enter coordinates of two different points:

Straight line given by points A[1; 3] and B[7; 2]

Calculation:

Slope-intercept form of line: y = -0.1667x+3.1667

Canonical form of the line equation: x+6y-19 = 0

Parametric form of the line equation:
x = 6t+1
y = -t+3      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 19

Y intercept: y0 = q = 3.1667

Distance line from the origin: d0 = 3.1236

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [4; 2.5]

Perpendicular Bisector equation: 6x-y-21.5 = 0


Vector OA = (1; 3) ;   |OA| = 3.1623
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 13
Angle ∠ AOB = 55°37'11″ = 0.9707 rad