Line slope calculator 3x-7y=-18
Straight line given by points A[1; 3] and B[8; 6]
Calculation:
Slope: m = 0.4286Slope-intercept form of line: y = 0.4286x+2.5714
Canonical form of the line equation: 3x-7y+18 = 0
Parametric form of the line equation:
x = 7t+1
y = 3t+3 ; t ∈ R
Slope angle of line: φ = 23°11'55″ = 0.4049 rad
X intercept: x0 = -6
Y intercept: y0 = q = 2.5714
Distance line from the origin: d0 = 2.3635
The length of the segment AB: |AB| = 7.6158
Vector: AB = (7; 3)
Normal vector: n = (3; -7)
Midpoint of the segment AB: M = [4.5; 4.5]
Perpendicular Bisector equation: 7x+3y-45 = 0
Vector OA = (1; 3) ; |OA| = 3.1623
Vector OB = (8; 6) ; |OB| = 10
Scalar product OA .OB = 26
Angle ∠ AOB = 34°41'43″ = 0.6055 rad