Line slope calculator 4x+9y=40
Straight line given by points A[1; 4] and B[10; 0]
Calculation:
Slope: m = -0.4444Slope-intercept form of line: y = -0.4444x+4.4444
Canonical form of the line equation: 4x+9y-40 = 0
Parametric form of the line equation:
x = 9t+1
y = -4t+4 ; t ∈ R
Slope angle of line: φ = -23°57'45″ = -0.4182 rad
X intercept: x0 = 10
Y intercept: y0 = q = 4.4444
Distance line from the origin: d0 = 4.0614
The length of the segment AB: |AB| = 9.8489
Vector: AB = (9; -4)
Normal vector: n = (4; 9)
Midpoint of the segment AB: M = [5.5; 2]
Perpendicular Bisector equation: 9x-4y-41.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 10
Angle ∠ AOB = 75°57'50″ = 1.3258 rad