Line slope calculator 3x+2y=11
Straight line given by points A[1; 4] and B[3; 1]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+5.5
Canonical form of the line equation: 3x+2y-11 = 0
Parametric form of the line equation:
x = 2t+1
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 3.6667
Y intercept: y0 = q = 5.5
Distance line from the origin: d0 = 3.0509
The length of the segment AB: |AB| = 3.6056
Vector: AB = (2; -3)
Normal vector: n = (3; 2)
Midpoint of the segment AB: M = [2; 2.5]
Perpendicular Bisector equation: 2x-3y+3.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (3; 1) ; |OB| = 3.1623
Scalar product OA .OB = 7
Angle ∠ AOB = 57°31'44″ = 1.0041 rad