Line slope calculator 3x+2y=11


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[3; 1]

Calculation:

Slope-intercept form of line: y = -1.5x+5.5

Canonical form of the line equation: 3x+2y-11 = 0

Parametric form of the line equation:
x = 2t+1
y = -3t+4      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 3.6667

Y intercept: y0 = q = 5.5

Distance line from the origin: d0 = 3.0509

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [2; 2.5]

Perpendicular Bisector equation: 2x-3y+3.5 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (3; 1) ;   |OB| = 3.1623
Scalar product OA .OB = 7
Angle ∠ AOB = 57°31'44″ = 1.0041 rad