Line slope calculator 4x+3y=16


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[4; 0]

Calculation:

Slope-intercept form of line: y = -1.3333x+5.3333

Canonical form of the line equation: 4x+3y-16 = 0

Parametric form of the line equation:
x = 3t+1
y = -4t+4      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 4

Y intercept: y0 = q = 5.3333

Distance line from the origin: d0 = 3.2

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [2.5; 2]

Perpendicular Bisector equation: 3x-4y+0.5 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (4; 0) ;   |OB| = 4
Scalar product OA .OB = 4
Angle ∠ AOB = 75°57'50″ = 1.3258 rad