Line slope calculator 2x+3y=14


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[4; 2]

Calculation:

Slope-intercept form of line: y = -0.6667x+4.6667

Canonical form of the line equation: 2x+3y-14 = 0

Parametric form of the line equation:
x = 3t+1
y = -2t+4      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 7

Y intercept: y0 = q = 4.6667

Distance line from the origin: d0 = 3.8829

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [2.5; 3]

Perpendicular Bisector equation: 3x-2y-1.5 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (4; 2) ;   |OB| = 4.4721
Scalar product OA .OB = 12
Angle ∠ AOB = 49°23'55″ = 0.8622 rad