Line slope calculator x-3y=-11
Straight line given by points A[1; 4] and B[4; 5]
Calculation:
Slope: m = 0.3333Slope-intercept form of line: y = 0.3333x+3.6667
Canonical form of the line equation: x-3y+11 = 0
Parametric form of the line equation:
x = 3t+1
y = t+4 ; t ∈ R
Slope angle of line: φ = 18°26'6″ = 0.3218 rad
X intercept: x0 = -11
Y intercept: y0 = q = 3.6667
Distance line from the origin: d0 = 3.4785
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; 1)
Normal vector: n = (1; -3)
Midpoint of the segment AB: M = [2.5; 4.5]
Perpendicular Bisector equation: 3x+y-12 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (4; 5) ; |OB| = 6.4031
Scalar product OA .OB = 24
Angle ∠ AOB = 24°37'25″ = 0.4298 rad