Line slope calculator x-3y=-11


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[4; 5]

Calculation:

Slope-intercept form of line: y = 0.3333x+3.6667

Canonical form of the line equation: x-3y+11 = 0

Parametric form of the line equation:
x = 3t+1
y = t+4      ; t ∈ R

Slope: m = 0.3333

Slope angle of line: φ = 18°26'6″ = 0.3218 rad

X intercept: x0 = -11

Y intercept: y0 = q = 3.6667

Distance line from the origin: d0 = 3.4785

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; 1)

Normal vector: n = (1; -3)

Midpoint of the segment AB: M = [2.5; 4.5]

Perpendicular Bisector equation: 3x+y-12 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (4; 5) ;   |OB| = 6.4031
Scalar product OA .OB = 24
Angle ∠ AOB = 24°37'25″ = 0.4298 rad