Line slope calculator 2x-3y=-10
Straight line given by points A[1; 4] and B[4; 6]
Calculation:
Slope: m = 0.6667Slope-intercept form of line: y = 0.6667x+3.3333
Canonical form of the line equation: 2x-3y+10 = 0
Parametric form of the line equation:
x = 3t+1
y = 2t+4 ; t ∈ R
Slope angle of line: φ = 33°41'24″ = 0.588 rad
X intercept: x0 = -5
Y intercept: y0 = q = 3.3333
Distance line from the origin: d0 = 2.7735
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; 2)
Normal vector: n = (2; -3)
Midpoint of the segment AB: M = [2.5; 5]
Perpendicular Bisector equation: 3x+2y-17.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (4; 6) ; |OB| = 7.2111
Scalar product OA .OB = 28
Angle ∠ AOB = 19°39'14″ = 0.343 rad