Line slope calculator 3x+4y=19
Straight line given by points A[1; 4] and B[5; 1]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+4.75
Canonical form of the line equation: 3x+4y-19 = 0
Parametric form of the line equation:
x = 4t+1
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 6.3333
Y intercept: y0 = q = 4.75
Distance line from the origin: d0 = 3.8
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [3; 2.5]
Perpendicular Bisector equation: 4x-3y-4.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 9
Angle ∠ AOB = 64°39'14″ = 1.1284 rad