Line slope calculator x-4y=-15
Straight line given by points A[1; 4] and B[5; 5]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+3.75
Canonical form of the line equation: x-4y+15 = 0
Parametric form of the line equation:
x = 4t+1
y = t+4 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -15
Y intercept: y0 = q = 3.75
Distance line from the origin: d0 = 3.638
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [3; 4.5]
Perpendicular Bisector equation: 4x+y-16.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 25
Angle ∠ AOB = 30°57'50″ = 0.5404 rad