Line slope calculator x-4y=-15


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[5; 5]

Calculation:

Slope-intercept form of line: y = 0.25x+3.75

Canonical form of the line equation: x-4y+15 = 0

Parametric form of the line equation:
x = 4t+1
y = t+4      ; t ∈ R

Slope: m = 0.25

Slope angle of line: φ = 14°2'10″ = 0.245 rad

X intercept: x0 = -15

Y intercept: y0 = q = 3.75

Distance line from the origin: d0 = 3.638

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; 1)

Normal vector: n = (1; -4)

Midpoint of the segment AB: M = [3; 4.5]

Perpendicular Bisector equation: 4x+y-16.5 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 25
Angle ∠ AOB = 30°57'50″ = 0.5404 rad