Line slope calculator 2x+5y=22
Straight line given by points A[1; 4] and B[6; 2]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+4.4
Canonical form of the line equation: 2x+5y-22 = 0
Parametric form of the line equation:
x = 5t+1
y = -2t+4 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 11
Y intercept: y0 = q = 4.4
Distance line from the origin: d0 = 4.0853
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [3.5; 3]
Perpendicular Bisector equation: 5x-2y-11.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (6; 2) ; |OB| = 6.3246
Scalar product OA .OB = 14
Angle ∠ AOB = 57°31'44″ = 1.0041 rad