Line slope calculator x-5y=-19


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[6; 5]

Calculation:

Slope-intercept form of line: y = 0.2x+3.8

Canonical form of the line equation: x-5y+19 = 0

Parametric form of the line equation:
x = 5t+1
y = t+4      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -19

Y intercept: y0 = q = 3.8

Distance line from the origin: d0 = 3.7262

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: 5x+y-22 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 26
Angle ∠ AOB = 36°9'29″ = 0.6311 rad