Line slope calculator x-5y=-19
Straight line given by points A[1; 4] and B[6; 5]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+3.8
Canonical form of the line equation: x-5y+19 = 0
Parametric form of the line equation:
x = 5t+1
y = t+4 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -19
Y intercept: y0 = q = 3.8
Distance line from the origin: d0 = 3.7262
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [3.5; 4.5]
Perpendicular Bisector equation: 5x+y-22 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 26
Angle ∠ AOB = 36°9'29″ = 0.6311 rad