Line slope calculator 4x-5y=-16


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[6; 8]

Calculation:

Slope-intercept form of line: y = 0.8x+3.2

Canonical form of the line equation: 4x-5y+16 = 0

Parametric form of the line equation:
x = 5t+1
y = 4t+4      ; t ∈ R

Slope: m = 0.8

Slope angle of line: φ = 38°39'35″ = 0.6747 rad

X intercept: x0 = -4

Y intercept: y0 = q = 3.2

Distance line from the origin: d0 = 2.4988

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; 4)

Normal vector: n = (4; -5)

Midpoint of the segment AB: M = [3.5; 6]

Perpendicular Bisector equation: 5x+4y-41.5 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (6; 8) ;   |OB| = 10
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad