Line slope calculator 4x-5y=-16
Straight line given by points A[1; 4] and B[6; 8]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+3.2
Canonical form of the line equation: 4x-5y+16 = 0
Parametric form of the line equation:
x = 5t+1
y = 4t+4 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -4
Y intercept: y0 = q = 3.2
Distance line from the origin: d0 = 2.4988
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [3.5; 6]
Perpendicular Bisector equation: 5x+4y-41.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (6; 8) ; |OB| = 10
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad