Line slope calculator 3x+7y=31


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.4286x+4.4286

Canonical form of the line equation: 3x+7y-31 = 0

Parametric form of the line equation:
x = 7t+1
y = -3t+4      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 10.3333

Y intercept: y0 = q = 4.4286

Distance line from the origin: d0 = 4.0705

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [4.5; 2.5]

Perpendicular Bisector equation: 7x-3y-24 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 12
Angle ∠ AOB = 68°50'19″ = 1.2015 rad