Line slope calculator 3x+7y=31
Straight line given by points A[1; 4] and B[8; 1]
Calculation:
Slope: m = -0.4286Slope-intercept form of line: y = -0.4286x+4.4286
Canonical form of the line equation: 3x+7y-31 = 0
Parametric form of the line equation:
x = 7t+1
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -23°11'55″ = -0.4049 rad
X intercept: x0 = 10.3333
Y intercept: y0 = q = 4.4286
Distance line from the origin: d0 = 4.0705
The length of the segment AB: |AB| = 7.6158
Vector: AB = (7; -3)
Normal vector: n = (3; 7)
Midpoint of the segment AB: M = [4.5; 2.5]
Perpendicular Bisector equation: 7x-3y-24 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 12
Angle ∠ AOB = 68°50'19″ = 1.2015 rad