Line slope calculator x+8y=33
Straight line given by points A[1; 4] and B[9; 3]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+4.125
Canonical form of the line equation: x+8y-33 = 0
Parametric form of the line equation:
x = 8t+1
y = -t+4 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 33
Y intercept: y0 = q = 4.125
Distance line from the origin: d0 = 4.0931
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [5; 3.5]
Perpendicular Bisector equation: 8x-y-36.5 = 0
Vector OA = (1; 4) ; |OA| = 4.1231
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 21
Angle ∠ AOB = 57°31'44″ = 1.0041 rad