Line slope calculator x+8y=33


Enter coordinates of two different points:

Straight line given by points A[1; 4] and B[9; 3]

Calculation:

Slope-intercept form of line: y = -0.125x+4.125

Canonical form of the line equation: x+8y-33 = 0

Parametric form of the line equation:
x = 8t+1
y = -t+4      ; t ∈ R

Slope: m = -0.125

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 33

Y intercept: y0 = q = 4.125

Distance line from the origin: d0 = 4.0931

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 8x-y-36.5 = 0


Vector OA = (1; 4) ;   |OA| = 4.1231
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 21
Angle ∠ AOB = 57°31'44″ = 1.0041 rad