Line slope calculator 5x+9y=50
Straight line given by points A[1; 5] and B[10; 0]
Calculation:
Slope: m = -0.5556Slope-intercept form of line: y = -0.5556x+5.5556
Canonical form of the line equation: 5x+9y-50 = 0
Parametric form of the line equation:
x = 9t+1
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -29°3'17″ = -0.5071 rad
X intercept: x0 = 10
Y intercept: y0 = q = 5.5556
Distance line from the origin: d0 = 4.8564
The length of the segment AB: |AB| = 10.2956
Vector: AB = (9; -5)
Normal vector: n = (5; 9)
Midpoint of the segment AB: M = [5.5; 2.5]
Perpendicular Bisector equation: 9x-5y-37 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 10
Angle ∠ AOB = 78°41'24″ = 1.3734 rad