Line slope calculator 5x+9y=50


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.5556x+5.5556

Canonical form of the line equation: 5x+9y-50 = 0

Parametric form of the line equation:
x = 9t+1
y = -5t+5      ; t ∈ R

Slope: m = -0.5556

Slope angle of line: φ = -29°3'17″ = -0.5071 rad

X intercept: x0 = 10

Y intercept: y0 = q = 5.5556

Distance line from the origin: d0 = 4.8564

The length of the segment AB: |AB| = 10.2956

Vector: AB = (9; -5)

Normal vector: n = (5; 9)

Midpoint of the segment AB: M = [5.5; 2.5]

Perpendicular Bisector equation: 9x-5y-37 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 10
Angle ∠ AOB = 78°41'24″ = 1.3734 rad