Line slope calculator 5x-9y=-40
Straight line given by points A[1; 5] and B[10; 10]
Calculation:
Slope: m = 0.5556Slope-intercept form of line: y = 0.5556x+4.4444
Canonical form of the line equation: 5x-9y+40 = 0
Parametric form of the line equation:
x = 9t+1
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 29°3'17″ = 0.5071 rad
X intercept: x0 = -8
Y intercept: y0 = q = 4.4444
Distance line from the origin: d0 = 3.8851
The length of the segment AB: |AB| = 10.2956
Vector: AB = (9; 5)
Normal vector: n = (5; -9)
Midpoint of the segment AB: M = [5.5; 7.5]
Perpendicular Bisector equation: 9x+5y-87 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (10; 10) ; |OB| = 14.1421
Scalar product OA .OB = 60
Angle ∠ AOB = 33°41'24″ = 0.588 rad