Line slope calculator 5x+2y=15


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[3; 0]

Calculation:

Slope-intercept form of line: y = -2.5x+7.5

Canonical form of the line equation: 5x+2y-15 = 0

Parametric form of the line equation:
x = 2t+1
y = -5t+5      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 3

Y intercept: y0 = q = 7.5

Distance line from the origin: d0 = 2.7854

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [2; 2.5]

Perpendicular Bisector equation: 2x-5y+8.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (3; 0) ;   |OB| = 3
Scalar product OA .OB = 3
Angle ∠ AOB = 78°41'24″ = 1.3734 rad