Line slope calculator 5x+2y=15
Straight line given by points A[1; 5] and B[3; 0]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+7.5
Canonical form of the line equation: 5x+2y-15 = 0
Parametric form of the line equation:
x = 2t+1
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 3
Y intercept: y0 = q = 7.5
Distance line from the origin: d0 = 2.7854
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [2; 2.5]
Perpendicular Bisector equation: 2x-5y+8.5 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (3; 0) ; |OB| = 3
Scalar product OA .OB = 3
Angle ∠ AOB = 78°41'24″ = 1.3734 rad