Line slope calculator 3x+2y=13


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[3; 2]

Calculation:

Slope-intercept form of line: y = -1.5x+6.5

Canonical form of the line equation: 3x+2y-13 = 0

Parametric form of the line equation:
x = 2t+1
y = -3t+5      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 4.3333

Y intercept: y0 = q = 6.5

Distance line from the origin: d0 = 3.6056

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [2; 3.5]

Perpendicular Bisector equation: 2x-3y+6.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (3; 2) ;   |OB| = 3.6056
Scalar product OA .OB = 13
Angle ∠ AOB = 45° = 0.7854 rad