Line slope calculator x+2y=11


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[3; 4]

Calculation:

Slope-intercept form of line: y = -0.5x+5.5

Canonical form of the line equation: x+2y-11 = 0

Parametric form of the line equation:
x = 2t+1
y = -t+5      ; t ∈ R

Slope: m = -0.5

Slope angle of line: φ = -26°33'54″ = -0.4636 rad

X intercept: x0 = 11

Y intercept: y0 = q = 5.5

Distance line from the origin: d0 = 4.9193

The length of the segment AB: |AB| = 2.2361

Vector: AB = (2; -1)

Normal vector: n = (1; 2)

Midpoint of the segment AB: M = [2; 4.5]

Perpendicular Bisector equation: 2x-y+0.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (3; 4) ;   |OB| = 5
Scalar product OA .OB = 23
Angle ∠ AOB = 25°33'36″ = 0.4461 rad