Line slope calculator 5x+3y=20
Straight line given by points A[1; 5] and B[4; 0]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+6.6667
Canonical form of the line equation: 5x+3y-20 = 0
Parametric form of the line equation:
x = 3t+1
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 4
Y intercept: y0 = q = 6.6667
Distance line from the origin: d0 = 3.43
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [2.5; 2.5]
Perpendicular Bisector equation: 3x-5y+5 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (4; 0) ; |OB| = 4
Scalar product OA .OB = 4
Angle ∠ AOB = 78°41'24″ = 1.3734 rad