Line slope calculator 5x+3y=20


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[4; 0]

Calculation:

Slope-intercept form of line: y = -1.6667x+6.6667

Canonical form of the line equation: 5x+3y-20 = 0

Parametric form of the line equation:
x = 3t+1
y = -5t+5      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 4

Y intercept: y0 = q = 6.6667

Distance line from the origin: d0 = 3.43

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [2.5; 2.5]

Perpendicular Bisector equation: 3x-5y+5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (4; 0) ;   |OB| = 4
Scalar product OA .OB = 4
Angle ∠ AOB = 78°41'24″ = 1.3734 rad