Line slope calculator x+3y=16
Straight line given by points A[1; 5] and B[4; 4]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+5.3333
Canonical form of the line equation: x+3y-16 = 0
Parametric form of the line equation:
x = 3t+1
y = -t+5 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 16
Y intercept: y0 = q = 5.3333
Distance line from the origin: d0 = 5.0596
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [2.5; 4.5]
Perpendicular Bisector equation: 3x-y-3 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (4; 4) ; |OB| = 5.6569
Scalar product OA .OB = 24
Angle ∠ AOB = 33°41'24″ = 0.588 rad