Line slope calculator 5x+4y=25


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -1.25x+6.25

Canonical form of the line equation: 5x+4y-25 = 0

Parametric form of the line equation:
x = 4t+1
y = -5t+5      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 5

Y intercept: y0 = q = 6.25

Distance line from the origin: d0 = 3.9043

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [3; 2.5]

Perpendicular Bisector equation: 4x-5y+0.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 5
Angle ∠ AOB = 78°41'24″ = 1.3734 rad