Line slope calculator 3x+4y=23
Straight line given by points A[1; 5] and B[5; 2]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+5.75
Canonical form of the line equation: 3x+4y-23 = 0
Parametric form of the line equation:
x = 4t+1
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 7.6667
Y intercept: y0 = q = 5.75
Distance line from the origin: d0 = 4.6
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [3; 3.5]
Perpendicular Bisector equation: 4x-3y-1.5 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 15
Angle ∠ AOB = 56°53'19″ = 0.9929 rad