Line slope calculator 4x+5y=29


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -0.8x+5.8

Canonical form of the line equation: 4x+5y-29 = 0

Parametric form of the line equation:
x = 5t+1
y = -4t+5      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 7.25

Y intercept: y0 = q = 5.8

Distance line from the origin: d0 = 4.529

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [3.5; 3]

Perpendicular Bisector equation: 5x-4y-5.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 11
Angle ∠ AOB = 69°13'40″ = 1.2083 rad