Line slope calculator 4x+5y=29
Straight line given by points A[1; 5] and B[6; 1]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+5.8
Canonical form of the line equation: 4x+5y-29 = 0
Parametric form of the line equation:
x = 5t+1
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 7.25
Y intercept: y0 = q = 5.8
Distance line from the origin: d0 = 4.529
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [3.5; 3]
Perpendicular Bisector equation: 5x-4y-5.5 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 11
Angle ∠ AOB = 69°13'40″ = 1.2083 rad