Line slope calculator 3x+5y=28
Straight line given by points A[1; 5] and B[6; 2]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+5.6
Canonical form of the line equation: 3x+5y-28 = 0
Parametric form of the line equation:
x = 5t+1
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 9.3333
Y intercept: y0 = q = 5.6
Distance line from the origin: d0 = 4.802
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [3.5; 3.5]
Perpendicular Bisector equation: 5x-3y-7 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (6; 2) ; |OB| = 6.3246
Scalar product OA .OB = 16
Angle ∠ AOB = 60°15'18″ = 1.0517 rad