Line slope calculator 5x+7y=40


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -0.7143x+5.7143

Canonical form of the line equation: 5x+7y-40 = 0

Parametric form of the line equation:
x = 7t+1
y = -5t+5      ; t ∈ R

Slope: m = -0.7143

Slope angle of line: φ = -35°32'16″ = -0.6202 rad

X intercept: x0 = 8

Y intercept: y0 = q = 5.7143

Distance line from the origin: d0 = 4.6499

The length of the segment AB: |AB| = 8.6023

Vector: AB = (7; -5)

Normal vector: n = (5; 7)

Midpoint of the segment AB: M = [4.5; 2.5]

Perpendicular Bisector equation: 7x-5y-19 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 8
Angle ∠ AOB = 78°41'24″ = 1.3734 rad