Line slope calculator 4x+7y=39
Straight line given by points A[1; 5] and B[8; 1]
Calculation:
Slope: m = -0.5714Slope-intercept form of line: y = -0.5714x+5.5714
Canonical form of the line equation: 4x+7y-39 = 0
Parametric form of the line equation:
x = 7t+1
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -29°44'42″ = -0.5191 rad
X intercept: x0 = 9.75
Y intercept: y0 = q = 5.5714
Distance line from the origin: d0 = 4.8374
The length of the segment AB: |AB| = 8.0623
Vector: AB = (7; -4)
Normal vector: n = (4; 7)
Midpoint of the segment AB: M = [4.5; 3]
Perpendicular Bisector equation: 7x-4y-19.5 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 13
Angle ∠ AOB = 71°33'54″ = 1.249 rad