Line slope calculator 4x+7y=39


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.5714x+5.5714

Canonical form of the line equation: 4x+7y-39 = 0

Parametric form of the line equation:
x = 7t+1
y = -4t+5      ; t ∈ R

Slope: m = -0.5714

Slope angle of line: φ = -29°44'42″ = -0.5191 rad

X intercept: x0 = 9.75

Y intercept: y0 = q = 5.5714

Distance line from the origin: d0 = 4.8374

The length of the segment AB: |AB| = 8.0623

Vector: AB = (7; -4)

Normal vector: n = (4; 7)

Midpoint of the segment AB: M = [4.5; 3]

Perpendicular Bisector equation: 7x-4y-19.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 13
Angle ∠ AOB = 71°33'54″ = 1.249 rad