Line slope calculator 3x+7y=38


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[8; 2]

Calculation:

Slope-intercept form of line: y = -0.4286x+5.4286

Canonical form of the line equation: 3x+7y-38 = 0

Parametric form of the line equation:
x = 7t+1
y = -3t+5      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 12.6667

Y intercept: y0 = q = 5.4286

Distance line from the origin: d0 = 4.9896

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [4.5; 3.5]

Perpendicular Bisector equation: 7x-3y-21 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (8; 2) ;   |OB| = 8.2462
Scalar product OA .OB = 18
Angle ∠ AOB = 64°39'14″ = 1.1284 rad