Line slope calculator x-8y=-39


Enter coordinates of two different points:

Straight line given by points A[1; 5] and B[9; 6]

Calculation:

Slope-intercept form of line: y = 0.125x+4.875

Canonical form of the line equation: x-8y+39 = 0

Parametric form of the line equation:
x = 8t+1
y = t+5      ; t ∈ R

Slope: m = 0.125

Slope angle of line: φ = 7°7'30″ = 0.1244 rad

X intercept: x0 = -39

Y intercept: y0 = q = 4.875

Distance line from the origin: d0 = 4.8374

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; 1)

Normal vector: n = (1; -8)

Midpoint of the segment AB: M = [5; 5.5]

Perpendicular Bisector equation: 8x+y-45.5 = 0


Vector OA = (1; 5) ;   |OA| = 5.099
Vector OB = (9; 6) ;   |OB| = 10.8167
Scalar product OA .OB = 39
Angle ∠ AOB = 45° = 0.7854 rad