Line slope calculator x-8y=-39
Straight line given by points A[1; 5] and B[9; 6]
Calculation:
Slope: m = 0.125Slope-intercept form of line: y = 0.125x+4.875
Canonical form of the line equation: x-8y+39 = 0
Parametric form of the line equation:
x = 8t+1
y = t+5 ; t ∈ R
Slope angle of line: φ = 7°7'30″ = 0.1244 rad
X intercept: x0 = -39
Y intercept: y0 = q = 4.875
Distance line from the origin: d0 = 4.8374
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; 1)
Normal vector: n = (1; -8)
Midpoint of the segment AB: M = [5; 5.5]
Perpendicular Bisector equation: 8x+y-45.5 = 0
Vector OA = (1; 5) ; |OA| = 5.099
Vector OB = (9; 6) ; |OB| = 10.8167
Scalar product OA .OB = 39
Angle ∠ AOB = 45° = 0.7854 rad