Line slope calculator 6x+y=12


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[2; 0]

Calculation:

Slope-intercept form of line: y = -6x+12

Canonical form of the line equation: 6x+y-12 = 0

Parametric form of the line equation:
x = t+1
y = -6t+6      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 2

Y intercept: y0 = q = 12

Distance line from the origin: d0 = 1.9728

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [1.5; 3]

Perpendicular Bisector equation: x-6y+16.5 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (2; 0) ;   |OB| = 2
Scalar product OA .OB = 2
Angle ∠ AOB = 80°32'16″ = 1.4056 rad