Line slope calculator 5x+y=11


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[2; 1]

Calculation:

Slope-intercept form of line: y = -5x+11

Canonical form of the line equation: 5x+y-11 = 0

Parametric form of the line equation:
x = t+1
y = -5t+6      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 2.2

Y intercept: y0 = q = 11

Distance line from the origin: d0 = 2.1573

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [1.5; 3.5]

Perpendicular Bisector equation: x-5y+16 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (2; 1) ;   |OB| = 2.2361
Scalar product OA .OB = 8
Angle ∠ AOB = 53°58'21″ = 0.942 rad