Line slope calculator 3x+y=9


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[2; 3]

Calculation:

Slope-intercept form of line: y = -3x+9

Canonical form of the line equation: 3x+y-9 = 0

Parametric form of the line equation:
x = t+1
y = -3t+6      ; t ∈ R

Slope: m = -3

Slope angle of line: φ = -71°33'54″ = -1.249 rad

X intercept: x0 = 3

Y intercept: y0 = q = 9

Distance line from the origin: d0 = 2.846

The length of the segment AB: |AB| = 3.1623

Vector: AB = (1; -3)

Normal vector: n = (3; 1)

Midpoint of the segment AB: M = [1.5; 4.5]

Perpendicular Bisector equation: x-3y+12 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (2; 3) ;   |OB| = 3.6056
Scalar product OA .OB = 20
Angle ∠ AOB = 24°13'40″ = 0.4229 rad