Line slope calculator x+2y=13
Straight line given by points A[1; 6] and B[3; 5]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+6.5
Canonical form of the line equation: x+2y-13 = 0
Parametric form of the line equation:
x = 2t+1
y = -t+6 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 13
Y intercept: y0 = q = 6.5
Distance line from the origin: d0 = 5.8138
The length of the segment AB: |AB| = 2.2361
Vector: AB = (2; -1)
Normal vector: n = (1; 2)
Midpoint of the segment AB: M = [2; 5.5]
Perpendicular Bisector equation: 2x-y+1.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (3; 5) ; |OB| = 5.831
Scalar product OA .OB = 33
Angle ∠ AOB = 21°30'5″ = 0.3753 rad