Line slope calculator 5x+3y=23


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[1; 6] and B[4; 1]

Calculation:

Slope: m = -1.6667

Slope-intercept form of line: y = -1.6667x+7.6667

Canonical form of the line equation: 5x+3y-23 = 0

Parametric form of the line equation:
x = 3t+1
y = -5t+6      ; t ∈ R

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 4.6

Y intercept: y0 = q = 7.6667

Distance line from the origin: d0 = 3.9445

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [2.5; 3.5]

Perpendicular Bisector equation: 3x-5y+10 = 0

Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 10
Angle ∠ AOB = 66°30'5″ = 1.1607 rad