Line slope calculator 4x-3y=-14
Straight line given by points A[1; 6] and B[4; 10]
Calculation:
Slope: m = 1.3333Slope-intercept form of line: y = 1.3333x+4.6667
Canonical form of the line equation: 4x-3y+14 = 0
Parametric form of the line equation:
x = 3t+1
y = 4t+6 ; t ∈ R
Slope angle of line: φ = 53°7'48″ = 0.9273 rad
X intercept: x0 = -3.5
Y intercept: y0 = q = 4.6667
Distance line from the origin: d0 = 2.8
The length of the segment AB: |AB| = 5
Vector: AB = (3; 4)
Normal vector: n = (4; -3)
Midpoint of the segment AB: M = [2.5; 8]
Perpendicular Bisector equation: 3x+4y-39.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (4; 10) ; |OB| = 10.7703
Scalar product OA .OB = 64
Angle ∠ AOB = 12°20'21″ = 0.2154 rad