Line slope calculator 2x-3y=-16
Straight line given by points A[1; 6] and B[4; 8]
Calculation:
Slope: m = 0.6667Slope-intercept form of line: y = 0.6667x+5.3333
Canonical form of the line equation: 2x-3y+16 = 0
Parametric form of the line equation:
x = 3t+1
y = 2t+6 ; t ∈ R
Slope angle of line: φ = 33°41'24″ = 0.588 rad
X intercept: x0 = -8
Y intercept: y0 = q = 5.3333
Distance line from the origin: d0 = 4.4376
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; 2)
Normal vector: n = (2; -3)
Midpoint of the segment AB: M = [2.5; 7]
Perpendicular Bisector equation: 3x+2y-21.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (4; 8) ; |OB| = 8.9443
Scalar product OA .OB = 52
Angle ∠ AOB = 17°6'10″ = 0.2985 rad