Line slope calculator 5x+4y=29
Straight line given by points A[1; 6] and B[5; 1]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+7.25
Canonical form of the line equation: 5x+4y-29 = 0
Parametric form of the line equation:
x = 4t+1
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 5.8
Y intercept: y0 = q = 7.25
Distance line from the origin: d0 = 4.529
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [3; 3.5]
Perpendicular Bisector equation: 4x-5y+5.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 11
Angle ∠ AOB = 69°13'40″ = 1.2083 rad