Line slope calculator 2x-4y=-22


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[5; 8]

Calculation:

Slope-intercept form of line: y = 0.5x+5.5

Canonical form of the line equation: 2x-4y+22 = 0

Parametric form of the line equation:
x = 4t+1
y = 2t+6      ; t ∈ R

Slope: m = 0.5

Slope angle of line: φ = 26°33'54″ = 0.4636 rad

X intercept: x0 = -11

Y intercept: y0 = q = 5.5

Distance line from the origin: d0 = 4.9193

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; 2)

Normal vector: n = (2; -4)

Midpoint of the segment AB: M = [3; 7]

Perpendicular Bisector equation: 4x+2y-26 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (5; 8) ;   |OB| = 9.434
Scalar product OA .OB = 53
Angle ∠ AOB = 22°32'35″ = 0.3935 rad