Line slope calculator 4x+5y=34
Straight line given by points A[1; 6] and B[6; 2]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+6.8
Canonical form of the line equation: 4x+5y-34 = 0
Parametric form of the line equation:
x = 5t+1
y = -4t+6 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 8.5
Y intercept: y0 = q = 6.8
Distance line from the origin: d0 = 5.3099
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [3.5; 4]
Perpendicular Bisector equation: 5x-4y-1.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (6; 2) ; |OB| = 6.3246
Scalar product OA .OB = 18
Angle ∠ AOB = 62°6'10″ = 1.0839 rad