Line slope calculator 3x+5y=33


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[6; 3]

Calculation:

Slope-intercept form of line: y = -0.6x+6.6

Canonical form of the line equation: 3x+5y-33 = 0

Parametric form of the line equation:
x = 5t+1
y = -3t+6      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 11

Y intercept: y0 = q = 6.6

Distance line from the origin: d0 = 5.6595

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: 5x-3y-4 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (6; 3) ;   |OB| = 6.7082
Scalar product OA .OB = 24
Angle ∠ AOB = 53°58'21″ = 0.942 rad