Line slope calculator 2x+5y=32


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[6; 4]

Calculation:

Slope-intercept form of line: y = -0.4x+6.4

Canonical form of the line equation: 2x+5y-32 = 0

Parametric form of the line equation:
x = 5t+1
y = -2t+6      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 16

Y intercept: y0 = q = 6.4

Distance line from the origin: d0 = 5.9423

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [3.5; 5]

Perpendicular Bisector equation: 5x-2y-7.5 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (6; 4) ;   |OB| = 7.2111
Scalar product OA .OB = 30
Angle ∠ AOB = 46°50'51″ = 0.8176 rad