Line slope calculator x+5y=31


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[6; 5]

Calculation:

Slope-intercept form of line: y = -0.2x+6.2

Canonical form of the line equation: x+5y-31 = 0

Parametric form of the line equation:
x = 5t+1
y = -t+6      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 31

Y intercept: y0 = q = 6.2

Distance line from the origin: d0 = 6.0796

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [3.5; 5.5]

Perpendicular Bisector equation: 5x-y-12 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 36
Angle ∠ AOB = 40°43'56″ = 0.7109 rad