Line slope calculator x+5y=31
Straight line given by points A[1; 6] and B[6; 5]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+6.2
Canonical form of the line equation: x+5y-31 = 0
Parametric form of the line equation:
x = 5t+1
y = -t+6 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 31
Y intercept: y0 = q = 6.2
Distance line from the origin: d0 = 6.0796
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [3.5; 5.5]
Perpendicular Bisector equation: 5x-y-12 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 36
Angle ∠ AOB = 40°43'56″ = 0.7109 rad