Line slope calculator 2x-5y=-28
Straight line given by points A[1; 6] and B[6; 8]
Calculation:
Slope: m = 0.4Slope-intercept form of line: y = 0.4x+5.6
Canonical form of the line equation: 2x-5y+28 = 0
Parametric form of the line equation:
x = 5t+1
y = 2t+6 ; t ∈ R
Slope angle of line: φ = 21°48'5″ = 0.3805 rad
X intercept: x0 = -14
Y intercept: y0 = q = 5.6
Distance line from the origin: d0 = 5.1995
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; 2)
Normal vector: n = (2; -5)
Midpoint of the segment AB: M = [3.5; 7]
Perpendicular Bisector equation: 5x+2y-31.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (6; 8) ; |OB| = 10
Scalar product OA .OB = 54
Angle ∠ AOB = 27°24'27″ = 0.4784 rad