Line slope calculator 2x-5y=-28


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[6; 8]

Calculation:

Slope-intercept form of line: y = 0.4x+5.6

Canonical form of the line equation: 2x-5y+28 = 0

Parametric form of the line equation:
x = 5t+1
y = 2t+6      ; t ∈ R

Slope: m = 0.4

Slope angle of line: φ = 21°48'5″ = 0.3805 rad

X intercept: x0 = -14

Y intercept: y0 = q = 5.6

Distance line from the origin: d0 = 5.1995

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; 2)

Normal vector: n = (2; -5)

Midpoint of the segment AB: M = [3.5; 7]

Perpendicular Bisector equation: 5x+2y-31.5 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (6; 8) ;   |OB| = 10
Scalar product OA .OB = 54
Angle ∠ AOB = 27°24'27″ = 0.4784 rad