Line slope calculator 5x+6y=41


Enter coordinates of two different points:

Straight line given by points A[1; 6] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -0.8333x+6.8333

Canonical form of the line equation: 5x+6y-41 = 0

Parametric form of the line equation:
x = 6t+1
y = -5t+6      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 8.2

Y intercept: y0 = q = 6.8333

Distance line from the origin: d0 = 5.2495

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 6x-5y-6.5 = 0


Vector OA = (1; 6) ;   |OA| = 6.0828
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 13
Angle ∠ AOB = 72°24'27″ = 1.2638 rad