Line slope calculator 5x+8y=53
Straight line given by points A[1; 6] and B[9; 1]
Calculation:
Slope: m = -0.625Slope-intercept form of line: y = -0.625x+6.625
Canonical form of the line equation: 5x+8y-53 = 0
Parametric form of the line equation:
x = 8t+1
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -32°19″ = -0.5586 rad
X intercept: x0 = 10.6
Y intercept: y0 = q = 6.625
Distance line from the origin: d0 = 5.618
The length of the segment AB: |AB| = 9.434
Vector: AB = (8; -5)
Normal vector: n = (5; 8)
Midpoint of the segment AB: M = [5; 3.5]
Perpendicular Bisector equation: 8x-5y-22.5 = 0
Vector OA = (1; 6) ; |OA| = 6.0828
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 15
Angle ∠ AOB = 74°11'51″ = 1.295 rad