Line slope calculator 8x+9y=80


Enter coordinates of two different points:

Straight line given by points A[1; 8] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.8889x+8.8889

Canonical form of the line equation: 8x+9y-80 = 0

Parametric form of the line equation:
x = 9t+1
y = -8t+8      ; t ∈ R

Slope: m = -0.8889

Slope angle of line: φ = -41°38'1″ = -0.7266 rad

X intercept: x0 = 10

Y intercept: y0 = q = 8.8889

Distance line from the origin: d0 = 6.6436

The length of the segment AB: |AB| = 12.0416

Vector: AB = (9; -8)

Normal vector: n = (8; 9)

Midpoint of the segment AB: M = [5.5; 4]

Perpendicular Bisector equation: 9x-8y-17.5 = 0


Vector OA = (1; 8) ;   |OA| = 8.0623
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 10
Angle ∠ AOB = 82°52'30″ = 1.4464 rad